In: Chemistry
8. Silver ion is found with an average concentration of 28 ppb in U.S. water supplies. (Assume the density of water is 1.0 g/cm3) a) What is the molarity of the silver ion?
Given the average concentration of silver is 28 ppb = 28 x0.001 mg/L Since 1 ppb = 0.001 mg/L
= 0.028 mg/L
= 0.028x10-3 g/L
Molar mass of silver is 107.9 g/mol
So number of moles of silver ion is = mass/molar mass
= (0.028x10-3 g) / (107.9 g/mol)
= 2.59x10-7 mol
So Molarity of silver ion , M = Number of moles / Volume of solution in L
= 2.59x10-7 mol / 1L
= 2.59x10-7 M