A bucket contains three red balls and four white balls. Two balls are drawn from the...

A bucket contains three red balls and four white balls. Two balls are drawn from the bucket in succession without replacement. What is the probability of getting two white balls, ie. a white ball on the first draw followed by a white ball on the second draw?

Expert Solution

A bucket contains three red balls and four white balls i.e a total of 7 balls.

Two balls are drawn from the bucket in succession without replacement.

P(Getting two white balls) = P(white ball on first draw) * P(White ball on second draw)

= Probability of getting a white ball out of 4 white balls * Probability of getting a white ball out of remaining 3 white balls

= (4C1 / 7C1) * (3C1 / 6C1)

= (4 / 7) * (3 / 6)

= 2/7 = 0.2857

The probability of getting two white balls is 0.2857.

orchestra answered 2 years ago

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