Question

In: Statistics and Probability

1- A machine fills cereal boxes. A random sample of 6 boxes had a mean of...

1-

A machine fills cereal boxes. A random sample of 6 boxes had a mean of 20.25 oz. The distribution is assumed to be NORMAL with KNOWN standard deviation of 0.21 oz.

Find a 99% Confidence Interval UPPER LIMIT?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

2-

A machine fills cereal boxes. A random sample of 6 boxes had a mean of 20.25 oz. The distribution is assumed to be NORMAL with KNOWN standard deviation of 0.21 oz.

Find a 80% Confidence Interval UPPER LIMIT?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

3-

A machine fills cereal boxes. A random sample of 6 boxes had a mean of 20.25 oz. The distribution is assumed to be NORMAL with KNOWN standard deviation of 0.21 oz.

Find the SAMPLE SIZE required to obtain a 0.1 Margin of Error for a 95% confidence interval.

Note: Enter X INTEGER with NO DECIMAL and round up. Thus, 7 is entered as 7, 3.5 is entered as 4, and 0.375 is entered as 0

Solutions

Expert Solution

PROBLEM 3 : Let us understand the 95% confidence interval first


Related Solutions

In a random sample of 35 boxes of cereal, the mean volume was 24.03 ounces. The...
In a random sample of 35 boxes of cereal, the mean volume was 24.03 ounces. The population standard deviation of the volume is known to be 0.005 ounces. Explain which distribution and which formula(s) you would use to construct a confidence interval for the population mean.
The weights of a random sample of cereal boxes that are supposed to weigh 1 pound...
The weights of a random sample of cereal boxes that are supposed to weigh 1 pound are given below. Estimate the standard deviation of the entire population with 91.5% confidence. Assume the population is normally distributed. 1.03, 0.99, 1.03, 1.03, 1.04, 1.03, 0.95, 1.01 LCL = UCL =
Lloyd's Cereal company packages cereal in 1 pound boxes (16 ounces). A sample of 25 boxes...
Lloyd's Cereal company packages cereal in 1 pound boxes (16 ounces). A sample of 25 boxes is selected at random from the production line every hour, and if the average weight is less than 15 ounces, the machine is adjusted to increase the amount of cereal dispensed. If the mean for 1 hour is 1 pound and the standard deviation is 0.2 pound, what is the probability that the amount dispensed per box will have to be increased?
A machine fills sugar boxes in such a way that the weights (in grams) are normally...
A machine fills sugar boxes in such a way that the weights (in grams) are normally distributed with a mean of 2260 g and a standard deviation of 20 g. Another machine checks the weights and rejects packages in the bottom 1% of weights and the top 1% of weights. Find the the minimum and maximum acceptable weights. Answer using whole numbers and enter the bottom 1% value in blank 1 and the top 1% in blank 2. i know...
QUESTION 1 A sample of weights of 50 boxes of cereal yield a sample average of...
QUESTION 1 A sample of weights of 50 boxes of cereal yield a sample average of 17 ounces. What would be the margin of error for a 90% CI of the average weight of all such boxes if the population deviation is 0.48 ounces? Round to the nearest hundredth QUESTION 2 A sample of heights of 117 American men yields a sample average of 57.04 inches. What would be the margin of error for a 95.44% CI of the average...
A cereal company claims that the mean weight of the cereal in its boxes is 14.8...
A cereal company claims that the mean weight of the cereal in its boxes is 14.8 oz. The weights (in ounces) of the cereal in a random sample of eight of its cereal boxes are listed below: 14.6, 13.8, 14.1, 13.7, 14.0, 14.4, 13.6, 14.2 Test the claim at the 0.01 significance level. Use the t test for the hypothesis of the mean.
The weights of a certain brand of cereal boxes are normally distributed. The mean weight of...
The weights of a certain brand of cereal boxes are normally distributed. The mean weight of a SAMPLE of 13 boxes was 14.91 ounces with a sample standard deviation of .22 ounces. The margin of error on a 90% confidence interval would be smaller than the margin of error on a 95% confidence interval. True or false?
1. A random sample of 28 students at a particular university had a mean age of...
1. A random sample of 28 students at a particular university had a mean age of 22.4 years. If the standard deviation of ages for all university students is known to be 3.1 years,Find a 90% confidence interval for the mean of all students at that university. SHOW WORK
1. A random sample of 4040 cars owned by students had a mean age of 7.37.3...
1. A random sample of 4040 cars owned by students had a mean age of 7.37.3 years and a standard deviation of 3.73.7 years, while a random sample of 2828 cars owned by faculty have a mean age of 5.85.8 years and a standard deviation of 3.53.5 years.    Use a 0.10.1 significance level to test the claim that, on average, cars owned by students are older than cars owned by faculty. The test statistic is ______________ The p-value is...
Q1. Does an average box of cereal contain 368 grams of cereal? A random sample of...
Q1. Does an average box of cereal contain 368 grams of cereal? A random sample of 36 boxes had a mean of 372.5 and a standard deviation of 12 grams. Test at the .05 level of significance.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT