In: Statistics and Probability
Suppose that the probability that any random student graduates with honors is 0.07. Also, we know that the probability of a student getting into grad school, given that they graduated with honors is 0.70. The probability of a student getting into grad school, given that they did not graduate with honors is 0.05. What is the probability that a student did not graduate with honors, given that the student did get in to graduate school?
A. 0.0514
B. 0.487
C. 0.513
D. 0.75
Solution:
Let
H = student graduates with honors and NH = student did not graduates with honors
the probability that any random student graduates with honors is 0.07.
thus
P(H) =0.07
thenP(NH ) =1 -P(H) = 1 - 0.07 = 0.93
Let G = a student getting into grad school,
the probability of a student getting into grad school, given that they graduated with honors is 0.70.
thus we have:
P(G|H) =0.70
and
The probability of a student getting into grad school, given that they did not graduate with honors is 0.05.
P(G|NH) =0.05
We have to find:
P( a student did not graduate with honors given that the
student did get in to graduate school) =............?
P(NH | G) =........?
Using Bayes rule:
Thus correct answer is: B. 0.487