In: Statistics and Probability
A study of seat belt users and nonusers yielded the randomly selected sample data summarized in the given table.
Number of cigarettes smoked per day
0 1-14 15 and over
Wear seat belts 185 30 50
Don't wear seat belts 155 25 55
At the 0.01 significance level, test the claim that the amount of smoking is independent of seat belt use. Which of the following is true?
Select one:
a. The expected value of the test statistics is 13.50 and the critical value is 4.60, hence we conclude that the amount of smoking is dependent on seat belt use
b. The expected value of the test statistics is 9.21 and the critical value is 5.72, hence we conclude that the amount of smoking is dependent on seat belt use
c. The expected value of the test statistics is 4.60 and the critical value is 9.21, hence we conclude that the amount of smoking is independent of seat belt use
d. The expected value of the test statistics is 5.72 and the critical value is 4.60, hence we conclude that the amount of smoking is dependent on seat belt use
e. None of the other answers in necessary true.
f. The expected value of the test statistics is 5.72 and the critical value is 9.21, hence we conclude that the amount of smoking is independent of seat belt use
Observed Frequencies | |||||||
0 | |||||||
0 | E | G | F | Total | |||
N | 185 | 30 | 50 | 265 | |||
M | 155 | 25 | 55 | 235 |
Expected frequency of a cell = sum of row*sum of column / total sum | |||||||
Expected Frequencies | |||||||
E | G | F | Total | ||||
N | 340*265/500=180.2 | 55*265/500=29.15 | 105*265/500=55.65 | 265 | |||
M | 340*235/500=159.8 | 55*235/500=25.85 | 105*235/500=49.35 | 235 |
(fo-fe)^2/fe | ||||||
N | 0.128 | 0.025 | 0.574 | |||
M | 0.144 | 0.028 | 0.647 |
Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe = 1.545
Level of Significance = 0.01
Number of Rows = 2
Number of Columns = 3
Degrees of Freedom=(#row - 1)(#column -1) = (2- 1 ) * ( 3- 1 )
= 2
Critical Value = 9.210
Decision: test statistic,X² < critical value , So, Do not reject
the null hypothesis
Please note that if data is correct than neither value in answer matches and hence below option can be done.
e. None of the other answers in necessary
true.
Please revert back in case of any doubt.
Please upvote. Thanks in advance.