In: Statistics and Probability
TYPE I |
TYPE II |
TYPE III |
128 |
166 |
168 |
TYPE I |
TYPE II |
TYPE III |
a.
Null Hypothesis H0: The chromosome damage during surgery with H2O2 is evenly distributed among three cell categories.
Alternative Hypothesis Ha: The chromosome damage during surgery with H2O2 is not evenly distributed among three cell categories.
b.
N = 128 + 166 + 168 = 462
Expected values = N * p where p = 1/3 (for evenly distributed)
= 462 * (1/3) = 154
TYPE I 154 |
TYPE II 154 |
TYPE III 154 |
c.
Based on a visual comparison between the actual sample and the expected values, the chromosome damage does not seem to be evenly distributed as the actual and expected values are quite different.
d.
If the distribution of damage is evenly among the cell categories, then there is a 3.7 % chance of obtaining the observed values or values farther from expected.
Since p-value is less than 0.05 significance level, we reject the null hypothesis.
Based on the P-value, We conclude that the chromosome damage is not evenly distributed among the three categories of cells because of low p-value.