A proton moves at 5.20 105 m/s in the horizontal direction. It enters a uniform vertical electric...

A proton moves at 5.20 10⁵ m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 10³ N/C. Ignore any gravitational effects.

(a) Find the time interval required for the proton to travel 5.50 cm horizontally.
ns

(b) Find its vertical displacement during the time interval in which it travels 5.50 cm horizontally. (Indicate direction with the sign of your answer.)
mm

(c) Find the horizontal and vertical components of its velocity after it has traveled 5.50 cm horizontally.
=

î + ĵ

km/s

Expert Solution

genius_generous answered 2 years ago

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