DIFFERENTIAL EQUATIONS: 1. A body with a weight of 3.5 grams force hangs from a spring...

DIFFERENTIAL EQUATIONS:

1. A body with a weight of 3.5 grams force hangs from a spring stretching it 3.21 centimeters.
Initially the body starts from rest 3.4 centimeters below its equilibrium position.
The medium in which the body moves offers a resistance force to movement that is numerically equal to 1/8 of its instantaneous speed.
Knowing that there is an external force, changing in time, which is defined by the formula: f (t) = 7cos (t) grams force.
Find the position in centimeters of the body after 5 seconds. Take positive above the equilibrium position. Consider positive downward and negative upward magnitudes

Expert Solution

genius_generous answered 2 years ago

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