In: Statistics and Probability
Given, there are,
4 linden trees,
5 brich trees,
And 2 bald cypress trees,
So, total number of trees to be planted is (4+5+2)=11 trees,
Now these 11 trees can be arranged( or planted) in a row (evenly spaced) in 11! ways.
But among these 11! possible arrangements, the 4 linden trees can arrange themselves in 4! ways, but since all the linden trees are identical, the ordering among the linden trees doesn't matter, similarly 5 white brich trees can be arranged among themselves in 5! ways, which also doesn't matter and lastly the 2 bald cypress trees can arrange among themselves in 2! ways, which also doesn't matter.
So, in total the trees of each type can be arranged amon themselves in 4!×5!×2! ways, which are to be ignored among the all possible 11! ways of arrangements,
So, the all possible ways the 11 trees (consisting of 4 linden, 5 white brich and 2 bald cypress) can be planted(or arranged) in a row (spaced evenly) in
So, all the trees xan be planted in a row spaced evenly in 6930 ways. Hence the answer.