Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in the formation of 0.2852 g of AgCl. Calculate the percentage of KCl in the sample?

%?

Expert Solution

KCl + AgNO3 ----------------------> AgCl + KNO3

74.55g 143.3 g

?? 0.2852 g

KCl needed = 74.55 x 0.2852 / 143.3

= 0.1484 g

% KCl = mass of KCl x 100 / sample mass

= 0.1484 x 100 / 0.2496

= 59.44 %

percentage of KCl in the sample = 59.44 %

queen_honey_blossom answered 2 years ago

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Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

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