In: Statistics and Probability
Record No. | Length-mm |
1 | 22 |
2 | 30 |
3 | 23 |
4 | 22 |
5 | 26 |
6 | 23 |
7 | 27 |
8 | 18 |
9 | 39 |
10 | 31 |
11 | 36 |
12 | 23 |
13 | 31 |
14 | 23 |
15 | 32 |
16 | 35 |
17 | 24 |
18 | 23 |
19 | 24 |
20 | 43 |
21 | 30 |
22 | 31 |
23 | 34 |
24 | 21 |
25 | 25 |
26 | 37 |
27 | 26 |
28 | 35 |
29 | 28 |
30 | 36 |
1. suppose you the fisher men want to use mosquito fish that are greater than 29 mm for bait, otherwise it is not worth using this lake to harvest bait fish.
a. state your research hypothesis, Ha and Ho.
a)
The null hypothesis, Ho: the average mosquito fish is
equal to 29 mm for bait. u =29
An alternative hypothesis, h1: the avearage mosquito fish are
greater than 29 mm for bait. u > 29
alpha = 5%
mean= 28.60 [Excel function used ->
AVERAGE]
sd= 6.229 [Excel function used ->
STDEV]
u= 29
n= 30.00 [Excel function used ->
COUNT]
alpha= 5%
critical value, t(a,n-1) = t(0.05,30-1) = 1.699
test statistic, t = (mean-u)/(sd/sqrt(n))
t = (28.6-29)/(6.229/sqrt(30))
t = -0.3517
p-value
(1-P(T<t)
1-P(T<-0.3517)
t.dist.rt(-0.3517,30-1)
0.636197
With t(29) = -0.35, p>5%, i fail to reject
Ho and conclude that the average mosquito fish is equal to
29 mm for bait.
That is there is no sufficient evidence to conclude that
the average mosquito fish are greater than 29 mm for bait. u >
29