Question

In: Statistics and Probability

In a meat packaging plant, Machine A accounts for 60% of the plant's output while Machine...

In a meat packaging plant, Machine A accounts for 60% of the plant's output while Machine B accounts for 40% of the plant's output. In total, 8% of the packages are improperly sealed. Also, 4% of the packages are from Machine A and are improperly sealed. If a package selected at random is improperly sealed, what is the probability that it came from machine A?

Expert Solution

Answer:

Given Data

TOPIC:Events and probability.

Define the following events as

1) Given that,

= 0.60

and

= 0.40 ( in decimals )

We need to find ,

[ conditional law of probability ]

[ Multilicative law of probaility ]

= 0.3

Again , P(of a package is improperly sealed)

= 1 -P ( of a package is properly sealed)

= 1 - P(S) [ law of complement events]

But , in total , 8% of the packages are improperly sealed.

= 1 - 0.92

= 0.08

***Please like it..

Thank you..

orchestra answered 2 years ago

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