Question

A: Assume that the mass of a person is 70kG and 8% of the body mass is blood. If the density of blood is 1.055g/mL, what is the blood volume?

B: Assume that the hematocrit (the ratio of the volume of red blood cells to the total volume of blood) ratio is 0.45, what is the plasma volume of this person?

C: Assume that the average life span of the red blood cell is 120 days. What volume of red blood cells is being destroyed each day? This corresponds to what volume of whole blood?

D: Assume that the hemoglobin concentration in the whole blood is 16g%. How much hemoglobin is degraded each day?

E: The molecular weight of hemoglobin is 66.6kg/mol and each hemoglobin binds four Fe atoms. How much iron is liberated from hemoglobin each day? Give the answer in mg/day and mol/day.

please answer it as soon as Possible. This Q worth a lot of point, Please don't answer it if you are not sure
I expect a long calculation.
Thank You

Answer 1

A) Total Body weight = 70 Kg

As given 8% of the body weight is blood, means 8 × 70/100 = 5.6 Kg of blood = 5600 g

Density of blood = 1.055 g/ml

Blood volume = Mass of blood / Density of blood

                        = 5600/1.055 = 5308.05 ml = 5.308 L

B) Hematocrit = Volume of RBC’s / Total volume of Blood

                        = 0.45

As we got above the total volume of blood = 5.308 L

Volume of RBC’S = Hematocrit * Total volume of blood

                              = 0.45 × 5.308 = 2.385 L = 2385 ml

C) Average lifespan of RBC’s = 120 Days

So, 2.385 Liters of blood will destroy in 120 days

Therefore, the volume of RBC’s is being destroyed each day = Total volume of RBC’s/120

                                                                                                   = 2.385/120 = 0.01987 = 0.0199 L

Means 19.9 ml of RBCs being destroyed per day

D)        Concentration of Hemoglobin in whole blood = 16 g% = 16 g/ 100ml

            Volume of whole blood we got = 5308 ml

            So, 16% of whole blood = 16 × 5308/100 = 849.28 ml

            When RBCs destroyed hemoglobin will also be degraded.

            Lifespan of RBCs is considered as Life span of hemoglobin

            Therefore in 120 days 849.28 ml of hemoglobin will get degraded

            Hemoglobin destroyed per day = total volume of Hb/120 = 849.28/120 = 7.07 ml

E) Molecular weight of Hb = 66.6 kg/mol = 66600 g/mol

Molecular weight of iron 56 g/mol

Each Hb binds with four iron ions, means 4×56 = 224 g of iron is present in each Hb atom

Percentage of Iron ions in Hb = 224/66600 = 0.33%

As we calculated above hemoglobin destroyed per day is 7.07 ml

This 7.07 ml of Hb contains 0.33% of iron = 7.07×033/100 = 0.002 g = 2 mg/day

4 moles (4 iron ions present in Hb) of iron contains 224 g of iron

224 g = 224000 mg = 4 mol

2 mg = ? moles

         = 2* 4/224000 = 3.5 × 10^-5 mol/day