A buffer solution based upon sulfurous acid was created by treating 1L of 1M sulfurous acid...

A buffer solution based upon sulfurous acid was created by treating 1L of 1M sulfurous acid with NaOH until a pH of 1.347 was achieved (assuming no volume change). To this buffer 1.170 moles of NaOH were added (assume no volume change). What is the final pH of this solution? Assume 5% assumption is valid.

Solutions

Expert Solution

moles of H2SO3 = 1 x 1 = 1

H2SO3 + NaOH --------------------> NaHSO3 + H2O

1 x 0

1-x 0 x

pH = pKa1 + log [NaHSO3 ]/[H2SO3 ]

1.347 = 1.85 + log ( x / 1-x)

x / 1- x = 0.314

x = 0.314 - 0.314 x

x = moles of NaHSO3 = moles of NaOH

moles of NaOH = 0.240

moles of H2SO3 = 1

on addition of 0.170 moles NaOH :

pH = 1.85 + log [0.240 + 0.170 / 1.0 -0.170]

pH = 1.54

final pH = 1.54

note : NaOH moles i think 0.170 moles not 1.170. if 1.170 moles NaOH is taken buffer will fail. verify once

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

a buffer solution based upon sulfurous acid (H2SO3) was created by treating 1.00 L of a...

a buffer solution based upon sulfurous acid (H2SO3) was created by treating 1.00 L of a 1.00 M sulfurous acid solution with NaOH until a pH of 1.323 was achieved (assuming no volume change). to this buffer 1.410 moles of NaOH were added (assume no volume change). what is the final pH of this solution? For this problem we can assume the 5% assumption is valid. (Ka1=1.5E-2 Ka2=1.0E-7) please explain how you solved this if possible.

Three buffers are made by combining a 1M solution of acetic acid with a 1M solution...

Three buffers are made by combining a 1M solution of acetic acid with a 1M solution of sodium acetate in the ratios shown below. 1M acetic acid 1M sodium acetate Buffer 1: 10mL 90mL Buffer 2: 50mL 50mL Buffer 3: 90mL 10mL If the pKa of acetic acid if 4,75, what is the pH of buffers 1-3? For this I got Buffer 1 = 5.70 Buffer 2 = 4.75 and Buffer 3 = 3.97 This next part is where I...

A 1.0 L of a buffer solution is created which is 0.363 M in hydrocyanic acid,...

A 1.0 L of a buffer solution is created which is 0.363 M in hydrocyanic acid, HCN, and 0.303 M sodium cyanate, NaCN. Ka for HCN = 4.0 x 10-10. What is the pH after 0.089 mol of HCl is added to the buffer solution?

A 1L buffer solution is 0.150M in HC7H5O2 and 0.250M in LiC7H5O2. Calculate the pH of...

A 1L buffer solution is 0.150M in HC7H5O2 and 0.250M in LiC7H5O2. Calculate the pH of the soln after the additon of 100mL of 1.00M HCl. The Ka HC7H5O2 = 6.5x10^-5

I want to make up 1L of 50mM phosphate buffer, pH 6.8. I have 1M phosphate...

I want to make up 1L of 50mM phosphate buffer, pH 6.8. I have 1M phosphate buffer, pH 12 and 2M HCl. How will I make up this buffer. Please explain! Thank you.

What is the pH of a 0.611 M solution of sulfurous acid? (Ka1 = 1.7 x...

What is the pH of a 0.611 M solution of sulfurous acid? (Ka1 = 1.7 x 10-2 and Ka2 = 6.2 x 10-8).

Each group will have a stock solution of 1M acetic acid and 1M sodium acetate. 2....

Each group will have a stock solution of 1M acetic acid and 1M sodium acetate. 2. Prepare 22mL buffer solution with 0.35M acetic acid and 0.35M sodium acetate. Given that the Ka of acetic acid is 1.8 x 10-5. What is the expected pH of the buffer? 3. Pipette the prepared buffer solution into two clean containers, each with 10mL buffer solution. Calculate and measure how the pH change if a. 2mL 0.025M NaOH is added to tube 1. b....

Buffer 1 is created such that the weak acid, HA, is 0.80 M and base, A–...

Buffer 1 is created such that the weak acid, HA, is 0.80 M and base, A– , is 0.80 M. Buffer 2 is created such that the weak acid, HA, is 0.080 M, and base, A– , is 0.080M. Which buffer has the greater buffer capacity? Briefly explain

How does a buffer resist change in pH upon addition of a strong acid?

How does a buffer resist change in pH upon addition of a strong acid? The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H^+ ions in solution and therefore only a little change in pH. The strong acid reacts with the weak acid in the buffer to form a weak base, which produces few H+ ions in solution and therefore only a little change in pH. The strong add reacts...

Concentration of acetic acid: 1.041M and concentration of sodium acetate is 1.071M. The buffer is created...

Concentration of acetic acid: 1.041M and concentration of sodium acetate is 1.071M. The buffer is created by mixing 100mL of acetic acid with 100mL of sodium acetate soluiton. a) What is the pH of 75mL of the buffer solution after the addition of 1mL of 3M NaOH? b) What is the pH of 75mL of the buffer solution after the addition of 5mL of 3M NaOH? c) What is the pH of 75mL of the buffer solution after the addition...

Subjects