Question

Two objects, one having three times the mass of the other, are dropped from the same height in a vacuum. At the end of their fall, their speeds are the same because: Select one: a. all objects reach the same terminal velocity b. the force of gravity is the same for both objects c. the acceleration of the largest object is three times greater than that of the smallest object d. no option displayed e. everything that falls into the void has constant speed

Answer 1

The correct answer would be option d. No option displayed here, because

Here we have given condition as,

M1 = 3 times of M2

Height is same in vacuum

And at the end of their fall, their speeds are the same because,

according to Newton’s Equation of motion

v2−u2=2as

where,
v = Final velocity of object
u = Initial velocity of object
a = Acceleration of object
s = Displacement made by object

Form the above equation we can say that v does not depend upon the mass of the object.

And accelerating force is given as,

F=Ma

Where
F = Force acting on the body
M= Mass of the object
a = Acceleration of the body

So Their Velocities will be equal but the force acting on them due to gravity is different.

Now,

In vaccines all the object have same acceleration irrespective of their mass. So If the two objects are released from the same height they will undergothe same acceleration, they will end their falling the same amount of time and with same velocities, irrespective of their masses.

Theforce of gravity, or weight, for each object will be proportional to its mass as above equation given

F = Ma.

The correct reason will be because they have same acceleration which is not given so none of the option is correct given here so option d will be correct.