In: Statistics and Probability
n = 200
p = 0.36
A.
Since np = 72 and n(1-p) = 128 10
Normal distribution
B.
Mean, = p = 0.36
C.
If n is increased to 500, then
np = 180 and n(1-p) = 320 10
Thus answer to part A won't' change.
Since the mean of the sampling distribution is independent of n, thus answer to part B also won't change.
D.
=
= 0.034
E.
P(>0.36) = P(Z>(0.36-0.36)/0.034)
= P(Z>0)
= 0.5
F.
P(0.3<0.4) = P((0.3-0.36)/0.034 < Z < (0.4-0.36)/0.034)
= P(-1.7647<Z<1.1765)
= 0.8415
G.
P(<0.28) = P(Z>(0.28-0.36)/0.034)
= P(Z>-2.353)
= 0.0093
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