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Mass in kg T20 Times for 20 cycles) Period (T) Period squared (T2) .10 9 .45...

Mass in kg	T₂₀ Times for 20 cycles)	Period (T)	Period squared (T²)
.10	9	.45	.2025
.20	12	.6	.36
.30	15	.75	.5625
.40	18	.9	.81

Amplitude (x0)=5 cm

Find the spring constant and value of q

Expert Solution

Given that :

amplitude, x₀ = 5 cm = 0.05 m

Total mass (in kg) : [(0.1) + (0.2) + (0.3) + (0.4)] kg

m = 1 kg

Total time-period squared (in s²) : [(0.2025) + (0.36) + (0.5625) + (0.81)] s²

T² = 1.93 s²

The spring constant which will be given as :

using an equation, T = 2m / k { eq.1 }

squaring on both sides, we get

T² = 4² (m / k)

k = 4² m / T² { eq.2 }

inserting the values in eq.2,

k = 4 (3.14)² (1 kg) / (1.93 s²)

k = (39.4 / 1.93) N/m

k = 20.4 N/m

genius_generous answered 2 years ago

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