You will compute absolute zero a) graphically and b) algebraically using the following two measurements: (Ti...

You will compute absolute zero a) graphically and b) algebraically using the following two measurements: (Ti = 25 C, Vi = 222 mL) and (Tf = 100 C, Vf = 279 mL). You are heating a gas at constant pressure, and it expands. You may leave everything in degrees Celsius and milliliters.

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Expert Solution

b) Given Vi = 222 mL, Ti = 25 C

Vf = 279 mL, Tf = 100 C

Suppose Ta be the absolute temperature and Va the corresponding volume ,then at constant pressure by Charles law ( note I'm using Charles law now not mentioning the scale because finally I will get an equation in terms of differences of temperatures so scales doesn't matter)

The above equation contains only difference in temperatures. At absolute temperature volume is zero Va =0

Rearranging we get

a) I have plotted the graph for you the temperature value at 0 volume is the absolute zero temperature which is -267.10 degree Celsius which matches with the algebraic calculation

genius_generous answered 1 year ago

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