In: Statistics and Probability
10.
Given that,
sample one, x1 =14, n1 =200, p1= x1/n1=0.07
sample two, x2 =54, n2 =300, p2= x2/n2=0.18
null, Ho: p1 = p2
alternate, H1: p1 < p2
level of significance, α = 0.05
from standard normal table,left tailed z α/2 =1.645
since our test is left-tailed
reject Ho, if zo < -1.645
we use test statistic (z) = (p1-p2)/√(p^q^(1/n1+1/n2))
zo =(0.07-0.18)/sqrt((0.136*0.864(1/200+1/300))
zo =-3.515
| zo | =3.515
critical value
the value of |z α| at los 0.05% is 1.645
we got |zo| =3.515 & | z α | =1.645
make decision
hence value of | zo | > | z α| and here we reject Ho
p-value: left tail - Ha : ( p < -3.5153 ) = 0.00022
hence value of p0.05 > 0.00022,here we reject Ho
ANSWERS
---------------
null, Ho: p1 = p2
alternate, H1: p1 < p2
test statistic: -3.515
critical value: -1.645
decision: reject Ho
p-value: 0.00022
we have enough evidence to support the claim that
Effect of NSAIDs (such as ibuprofen) on injured law enforcement
personnel to decrease fever, pain, and swelling.