Question

In: Statistics and Probability

The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet)...

The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet) when stopping on a dry surface are shown in the table. Can you conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry suffice? Use alph = 0.01.

​Weight, x

5910

5350

6500

5100

5850

4800

Variability in braking​ distance, y

1.79

1.99

1.91

1.55

1.68

1.50

Setup the hypotheis for the test

Idenfity the critical values. Round to three decimal places

Calculate the test statistic

Solutions

Expert Solution

Weight X Braking Distance Y X * Y
5910 1.79 10578.9 34928100 3.2041
5350 1.99 10646.5 28622500 3.9601
6500 1.91 12415 42250000 3.6481
5100 1.55 7905 26010000 2.4025
5850 1.68 9828 34222500 2.8224
4800 1.5 7200 23040000 2.25
Total 33510 10.42 58573.4 1.89E+08 18.2872

To Test :-

H0 :-  

H1 :-  


Test Statistic :-


t = 1.5951


Test Criteria :-
Reject null hypothesis if

-4.6041 < 1.5951 < 4.6041
Result :- We fail to Reject null hypothesis


Decision based on P value
P - value = P ( t > 1.5951 ) = 0.1859
Reject null hypothesis if P value < level of significance
P - value = 0.1859 > 0.01 ,hence we fail to reject null hypothesis
Conclusion :- We Accept H0

There is no linear correlation between two variables.



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