In: Statistics and Probability
The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet) when stopping on a dry surface are shown in the table. Can you conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry suffice? Use alph = 0.01.
Weight, x
5910
5350
6500
5100
5850
4800
Variability in braking distance, y
1.79
1.99
1.91
1.55
1.68
1.50
Setup the hypotheis for the test
Idenfity the critical values. Round to three decimal places
Calculate the test statistic
Weight X | Braking Distance Y | X * Y | |||
5910 | 1.79 | 10578.9 | 34928100 | 3.2041 | |
5350 | 1.99 | 10646.5 | 28622500 | 3.9601 | |
6500 | 1.91 | 12415 | 42250000 | 3.6481 | |
5100 | 1.55 | 7905 | 26010000 | 2.4025 | |
5850 | 1.68 | 9828 | 34222500 | 2.8224 | |
4800 | 1.5 | 7200 | 23040000 | 2.25 | |
Total | 33510 | 10.42 | 58573.4 | 1.89E+08 | 18.2872 |
To Test :-
H0 :-
H1 :-
Test Statistic :-
t = 1.5951
Test Criteria :-
Reject null hypothesis if
-4.6041 < 1.5951 < 4.6041
Result :- We fail to Reject null hypothesis
Decision based on P value
P - value = P ( t > 1.5951 ) = 0.1859
Reject null hypothesis if P value <
level of significance
P - value = 0.1859 > 0.01 ,hence we fail to reject null
hypothesis
Conclusion :- We Accept H0
There is no linear correlation between two variables.