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The specific rate constant for the first-order decomposition of N2O5(g) to NO2(g) and O2(g) is 7.48×10−3s−1...

The specific rate constant for the first-order decomposition of N2O5(g) to NO2(g) and O2(g) is 7.48×10−3s−1 at a given temperature. Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.100 atm to rise to 0.220 atm .

Solutions

Expert Solution

                     

Initial               0.100            0                    0

Final              (0.100-x)        2x                  0.5x

Final Pressure = (0.100-x) + 2x + 0.5x = 0.100 + 1.5x = 0.220

1.5x = 0.120

x = 0.080

For the first order decomposition

Ao = 0.100 atm, At = 0.020 atm

ln(Ao/At) = kt

ln(0.100/0.020) = (7.48 * 10^(-3)) * t

t = 1000 * ln(5)/7.48 = 215.165 seconds

queen_honey_blossom answered 2 years ago
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