In: Physics
consider the potential v(y,z) =sinky(Ce^kz + De^-kz)
apply the two boundary conditions
a- V(y,z=b)=0
b- V(y=a,z)=0
Equation of the given potential is,
the first boundery condition states,
V(y,z=b)=0 ie V=0 for z=b,
putting z=b in eq 1 we get,
since y is a variable and can have any values hence we cannot take sin ky=0 ,hence,
putting the value of D in eq 1 we will get,
the second boundary condition states,
V(y=a,z)=0 , ie V=0 for y=a;
putting y=a in eq 2 we get,
since z is a variable and can have any values hence we cannot take ,hence,
putting this in eq 2 we will get,
where