Question
In: Statistics and Probability
When the background music tempo was slow, the mean amount of bar purchases for a sample...
When the background music tempo was slow, the mean amount of bar purchases for a sample of 17 restaurant patrons was $30.52 with a standard deviation of $15.20. When the background music tempo was fast, the mean amount of bar purchases for a sample of 12 patrons in the same restaurant was $21.71 with a standard deviation of $9.10. Assuming equal variances, at α = 0.10, is the true mean higher when the music is slow?
Solutions
orchestra answered 2 years agoRelated Solutions
When the background music was slow, the mean amount of bar purchases for a sample of...
When the background music was slow, the mean amount of bar
purchases for a sample of
17 restaurant patrons was $30.47 with a standard deviation of
$15.10. When the background
music was fast, the mean amount of bar purchases for a sample of
14 patrons in the same
restaurant was $21.62 with a standard deviation of $9.50.
(a) Assuming equal variances, at a significance level
α=.01, is the mean amount of bar purchases higher when the music
is slow?
(b)...
An investigator wonders if slow-tempo music is more complex than fast-tempo music – since with slower...
An investigator
wonders if slow-tempo music is more complex than fast-tempo music –
since with slower music, the listener has more time to process the
incoming musical information. To study this, he examines three
samples of pop songs by the Beatles that differ in tempo: slow
(group 1), moderate (group 2), and fast (group 3). 20 Beatles songs
are sampled in each category (so, 60 songs total). As a measure of
musical complexity, the investigator counts the number of different...
1)What is a sampling distribution for the sample mean, x-bar? Explain. Is x-bar a random variable?...
1)What is a sampling distribution for the sample mean, x-bar?
Explain. Is x-bar a random variable? Why do you think so?
2) We learned standard error of the mean ( read sigma xbar in
denotation) or standard deviation of sample mean. When the size(n)
of the sample collected from a infinite population is greater than
1, why is the standard error of the mean smaller than
the standard deviation of X, population ? Explain conceptually
or/and algebraically. Think of formula for...
A random sample of 20 purchases showed the amounts in the table (in $). The mean...
A random sample of 20 purchases showed the amounts in the table
(in $). The mean is $50.76 and the standard deviation is
$19.48
a) Construct a 80% confidence interval for the mean purchases of
all customers, assuming that the assumptions and conditions for
the confidence interval have been met.
b) How large is the margin of error?
c) How would the confidence interval change if you had assumed
that the standard deviation was known to be $20?
60.91
64.3...
A random sample of 20 purchases showed the amounts in the table (in $). The mean...
A random sample of 20 purchases showed the amounts in the table
(in $). The mean is $49.88 and the standard deviation is
$20.86.
B) What is the margin of error ?A) Construct a 80% confidence
interval for the mean purchases of all customers, assuming that
assumptions and conditions for confidence interval have been met.
(What is the confidence interval) ?
C) How would the confidence interval change if you had assumed
that the standard deviation was known to be...
A random sample of 2020 purchases showed the amounts in the table (in $). The mean...
A random sample of
2020
purchases showed the amounts in the table (in $). The mean
is
$49.8149.81
and the standard deviation is
$21.9521.95.
a) Construct a
8080%
confidence interval for the mean purchases of all customers,
assuming that the assumptions and conditions for the confidence
interval have been met.
b) How large is the margin of error?
c) How would the confidence interval change if you had assumed
that the standard deviation was known to be
$2222?
A) The...
A random sample of 20 purchases showed the amounts in the table (in $). The mean...
A random sample of 20 purchases showed the amounts in the
table (in $). The mean is
$49.71 and the standard deviation is $20.12
a) Construct a 99% confidence interval for the mean purchases of
all customers, assuming that the assumptions and conditions for
the confidence interval have been met.
b) How large is the margin of error?
c) How would the confidence interval change if you had assumed
that the standard deviation was known to be
$21?
40.97
68.94...
Suppose you randomly sample 64 cans and find the mean amount of Coke in this sample...
Suppose you randomly sample 64 cans and find the mean amount of
Coke in this sample is 11.85 ounces and the standard deviation is
0.35 ounces. Construct a 95% confidence interval estimate for the
mean amount of Coke in the all such cans.
In a sample of credit card holders the mean monthly value of credit card purchases was...
In a sample of credit card holders the mean monthly value of
credit card purchases was $ 298 and the sample variance was 53 ($
squared). Assume that the population distribution is normal. Answer
the following, rounding your answers to two decimal places where
appropriate.
A.) Suppose the sample results were obtained from a random
sample of 13 credit card holders. Find a 95% confidence interval
for the mean monthly value of credit card purchases of all card
holders.
B.)...
Based on past data, the sample mean of the credit card purchases at a large department...
Based on past data, the sample mean of the credit card purchases
at a large department store is $45. Assuming sample size is 25 and
the sample standard deviation is 9.
a) What % of
samples are likely to have between 25 and 35?
___________
b) Between what two
values 95% of sample means
fall?
___________
c) Below
what value 98% of sample means
fall?
___________
d) Above what
value only5% of sample means
fall??
___________...
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