In: Chemistry
Calculate the pH of an aqueous solution that is 1.0 M Na2CO3. Ka2 for H2CO3 is 4.7 × 10-11. Please post full work and explanation. Thank you.
Na2CO3 concentration = 1.0
Kb1 = Kw / Ka2
= 1.0 x 10^-14 / 4.7 x 10^-11
= 2.13 x 10^-4
CO32- + H2O -------------> HCO3- + OH-
1.0 0 0
1.0 - x x x
Kb1 = x^2 / 1.0 - x
2.13 x 10^-4 = x^2 / 1 - x
x = 0.0145
[OH-] = 0.0145 M
[H+] = 6.89 x 10^-13 M
pH = -log (6.90 x 10^-13)
pH = 12.16