Question

In: Statistics and Probability

As a packet delivery driver, I load my van with 40 packets each day. The average...

As a packet delivery driver, I load my van with 40 packets each day. The average weight of a packet I carry is 10kg, with a standard deviation of 4kg. If X is the total weight of the packets, what is the probability that this weight is:

a. Exactly 400kg

b. Less than 400kg

c. More than 500kg.

d. Between 450 and 500kg

Solutions

Expert Solution

Let us assume that the weight of each packet follows Normal distribution with the given parameters as mean 10 kg and standard deviation of 4 kg.

Let X be the total weight of 40 packets loaded in a delivery van.

We use following property of Normal distribution to find the distribution of X.

Central limit theorem:

If { Yi , i=1,2,...,n } are i.i.d. Normal variables with mean= m and Standard deviation = s

then, sum(Yi) follows Normal with mean= n*m and standard deviation = sqrt(n)*s

Hence, X follows Normal distribution with mean = 40*10 = 400 and standard deviation = sqrt(40)*4 = 25.3

According to the prpoerties of Normal distribution Z=(X-400)/25.3 follows Standard Normal distribution.

Question a) -

We can't use the regular probability tables to calculate the probability of single point.

We use R-studio to find the probability at X=400. Use the following command in R to get the probability.

dnorm(400,mean=400,sd=25.3)

This gives answer, P( X=400 ) = 0.01576

The probability that the weight is exactly 400 kg is 0.01576.

Question b) -

We know that Normal distribution is symmetric around its mean. That is P( X< mean)= ( X>mean) = 0.5

Here the mean of X is 400 kg. Hence, P( X<400 )= 0.5

The probability that the weight is less than 400 kg is 0.5.

Question c) -

Use the following R command to calculate the probability

1-pnorm(3.9526,mean=0,sd=1)

P( X>500 ) = P( (X-400)/25.3 > (500-400)/25.3 ) = P( Z > 3.9526 ) = 0.0000386

Hence,  P( X>500 ) = 0

The probability that the weight is more than 500 kg is almost 0.

Question d) -

P( 450<X<500 ) = P( (450-400)/25.3 <Z< (500-400)/25.3 ) = P( 1.9763 < Z < 3.9526 ) = P(Z<3.9526) - P(Z<1.9763)

= 1 - 0.9772 = 0.0228

The probability that the weight is between 450 and 500 kg is 0.0228.

I hope you find the solution helpful. If you have any doubt then feel free to ask in the comment section.

Please do not forget to vote the answer.

Thank you in advance!!!


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