Question

A carpenter tosses a shingle horizontally off a roof at an initial velocity u = 17m/s. The shingle travels a distance d = 20.0 m in the horizontal direction. You may assume that the acceleration Je to gravity is 9.8 m/s^2.  

Draw a vertical position vs. horizontal position (y vs. x) plot. Label the known Quantities in the plot.  

How long does it take the shingle to reach the ground?  

What is the height of the roof that the shingle was tossed from?

Answer 1

step;1

Given that

initial velocity u=17 m/s

range R=20 m

acceleration due to gravity g=9.8 m/s^2

step;2

now we find the angle does the body travels

20=17^2*sin(2theta)/9.8

196/17^2=sin(2thata)

0.68=sin(2 thata)

2 theta=sin^-1[0.68]

theta=42.8/2=21.4 degree

step;3

now we find the time of the flight

the time of the flight T=2*17*sin(21.4)/9.8=1.3 sec

step;4

now we find the height

the height H=17^2*sin^2(21.4)/19.6=1.96 m