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By what potential distance must an electron (m0=9.11*10^-31 kg), be accelerated to have wavelength of 5.47*10^-12...

By what potential distance must an electron (m0=9.11*10^-31 kg), be accelerated to have wavelength of 5.47*10^-12 m?

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Expert Solution

We know that from debroglie wavelength associated with particle is given by

                          lamda =h/Sqrt(2mqV)

Thefore potenrial diffrence required to accelerate proton is V =h2/2*m*q*lamda2

                                                                                                = (6.625*10-34)2/2*1.67E-27 kg*1.6*10-19*(5.07E-12 m)2 =33.34V

Thefore potenrial diffrence required to accelerate electron is V =h2/2*m*q*lamda2

                                                                                                = (6.625*10-34)2/2*9.11E-31 kg*1.6*10-19*(5.07E-12 m)2 =5.857*104V

genius_generous answered 1 hour ago
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