In: Statistics and Probability
When 355 college students are randomly selected and surveyed, it is found that 129 own a car. Construct a 96% confidence interval for the percentage of all college students who own a car. (3 decimal places)
Solution :
n = 355
x = 129
= x / n = 129 / 355 = 0.363
1 - = 1 - 0.363 =0.637
At 96% confidence level the z is ,
= 1 - 96% = 1 - 0.96 = 0.04
/ 2 = 0.04 / 2 = 0.02
Z/2 = Z0.02 = 2.054
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.054 * (((0.363 * 0.637) / 355)
= 0.052
A 96 % confidence interval for population proportion p is ,
- E < P < + E
0.363 - 0.052 < p < 0.363 + 0.052
0.311 < p < 0.415
21.1% < P < 41.5%