In: Finance
Assume that you borrow $36,000 for six years at an interest rate of 3.6% per year. If the loan has monthly payments, what is the amount of principal in the first payment? Question 5 options: A) $448.69 B) $556.69 C) $462.59 D) $477.86 E) $522.86
Option a. 448.69 is correct:
| Monthly payment | = | [P * R * (1+R)^N ] / [(1+R)^N -1] | |
| Using the formula: | |||
| Principle | P | 36,000.00 | |
| Rate of interest per period: | |||
| Annual rate of interest | 3.600% | ||
| Frequency of payment | = | Once in 1 month period | |
| Numer of payments in a year | = | 12/1 = | 12 |
| Rate of interest per period | R | 0.036 /12 = | 0.3000% |
| Total number of payments: | |||
| Frequency of payment | = | Once in 1 month period | |
| Number of years of loan repayment | = | 6 | |
| Total number of payments | N | 6*12 = | 72 |
| Period payment using the formula | = | [ 36000*0.003*(1+0.003)^72] / [(1+0.003 ^72 -1] | |
| Monthly payment | = | 556.69 |
| Period | Opening liability | Interest expense | EMI Payment | Principle repaid | Closing liability |
| N | A | B= A* 0.0030 | C | D=C-B | E=A-D |
| 1 | 36,000.00 | 108.00 | 556.69 | 448.69 | 35,551.31 |
principle portion = 448.69