Question

In: Math

The number of pig farms is increasing, a study was conducted to test if composted pig...

The number of pig farms is increasing, a study was conducted to test if composted pig manure might be a better fertilizer than composted cow manure. Eight corn fields of equal size were chosen for the experiment. One half of each corn field was fertilized with composted cow manure and the other half was fertilized with composed pig manure. The yields are given in the following table.

Field

1

2

3

4

5

6

7

8

Mean

Std Dev

Cow

85

80

110

115

105

110

85

110

100

13.2288

Pig

95

100

120

110

125

120

120

130

115

11.4564

Differences

-10

-20

-10

5

-20

-10

-35

-20

-15

10.8972

Test at a = 0.01 the claim that the average yield is higher for composted pig manure than it is for composted cow manure.

Solutions

Expert Solution

µd =µcow - µpig

Ho :   µd=   0
Ha :   µd <   0

mean of difference ,    D̅ =    -15.000                  
                          
std dev of difference , Sd =        10.8972                  
                          
std error , SE = Sd / √n =    10.8972   / √   8   =   3.8527      
                          
t-statistic = (D̅ - µd)/SE = (   -15   -   0   ) /    3.8527   =   -3.8933
                          
Degree of freedom, DF=   n - 1 =    7                  
  
p-value =        0.0030   [excel function: =t.dist(t-stat,df) ]              
Decision:   p-value <α , Reject null hypothesis                      
there is enough evidence to support the claim that the average yield is higher for composted pig manure than it is for composted cow manure


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