In: Physics
Q1/ The current in an RL circuit builds up to one-third of its steady-state value in 6.25 s. Find the inductive time constant.
Q2/ A coil is connected in series with a 14.3 kΩ resistor. An ideal 48.4 V battery is applied across the two devices, and the current reaches a value of 2.37 mA after 4.78 ms. (a) Find the inductance of the coil. (b) How much energy is stored in the coil at this same moment?
SOLUTION:
Q-1)
t= 6.25 s
Lets the inductive time constant.=
we know that
ANSWER = 15.41 s
Q2)
a) R =14.3 =14.3*103
V= 48.4 V
I= 2.37 mA =2.37*10-3 A
t = 4.78*10-3 s
we know the formula of
then L= the inductance of the coil.
we're applying this inductance formula
the inductance of the coil. IS = 56.74 H
AND
b) The energy is stored in the coil at this same moment E
OR