Question

In: Chemistry

A solution is made by dissolving 0.4352g of nickel through water to make a 500.0 mL...

A solution is made by dissolving 0.4352g of nickel through water to make a 500.0 mL solution. A dilution is made by pipeting 2.00 mL into a 250.0 mL volumetric flask and bring it to volume with distilled water. What is the parts per million, ppm, concentration of nickel in the dilution?

Solutions

Expert Solution

We know that 1 ppm = 1 mg/L

The concentration of the stock solution is = 0.4352 g / 500.0 mL

                                                            = 0.4352x103 mg / 0.5 L

                                                            = 870.4 mg/L

                                                            = 870.4 ppm

So the concentration of 2.00 mL stock solution is also 870.4 ppm

According to law of dilution   MV = M'V'

Where M = Molarity of stock = 870.4 ppm

V = Volume of the stock = 2.0 mL

M' = Molarity of dilute solution = ?

V' = Volume of the dilute solution = 250.0 mL

Plug the values we get   , M' = MV /V'

                                          = ( 870.4 x 2.0) / 250.0

                                          = 6.963 ppm

Therefore the concentration of the dilute solution is 6.963 ppm


Related Solutions

Consider a solution made by mixing 500.0 mL of 0.03158 M Na2HAsO4 with 500.0 mL of...
Consider a solution made by mixing 500.0 mL of 0.03158 M Na2HAsO4 with 500.0 mL of 0.04202 M NaOH. Complete the mass balance expressions below for Na and arsenate species in the final solution. [Na+] = ____ M [HAsO42-] + [__] + [__] + [__] = ____ M
A solution is made by dissolving 40.0 g of KOH in 100 mL of water (density...
A solution is made by dissolving 40.0 g of KOH in 100 mL of water (density 0.995 g/mL) to form a solution. What is the mass percent solute in the solution? 1. 40.2% 2. 40.0% 3. 3.49% 4. 28.6% 5. 28.7%
A solution is made by mixing exactly 500.0 mL of 0.167 M NaOH with exactly 500.0...
A solution is made by mixing exactly 500.0 mL of 0.167 M NaOH with exactly 500.0 mL of 0.100 M CH3COOH. Calculate the equilibrium concentrations of H3O+, CH3COOH, CH3COO-, OH-, and Na+. [H3O+] = M [CH3COOH] =    M [CH3COO-] =    M [OH-] = M [Na+] = M
A solution is prepared by dissolving 171g of CdCl2 in enough water to make 250.0 mL...
A solution is prepared by dissolving 171g of CdCl2 in enough water to make 250.0 mL of solution. If the density of the solution is 1.556 g/mL, calculate: Molarity of the solution, mole fraction of CdCl2, and molality of the solution.
A solution is prepared by dissolving 46.5 mL of methanol in 130.0 mL of water at...
A solution is prepared by dissolving 46.5 mL of methanol in 130.0 mL of water at 25 ∘C. The final volume of the solution is 169.5 mL . The densities of methanol and water at this temperature are 0.782 g/mL and 1.00 g/mL , respectively. For this solution, calculate each of the following. A.) molarity B.)molality C.)percent by mass D.)mole fraction E.)mole percent
A solution is made by dissolving 0.0100 mol of HF in 1.00 kg of water. The...
A solution is made by dissolving 0.0100 mol of HF in 1.00 kg of water. The solution was found to freeze at –0.0236 °C. Calculate the value of i and estimate the percent ionization of HF in this solution. i =____ so HF is ______
A solution is made by dissolving 0.0100 mol of HF in 1.00 kg of water. The...
A solution is made by dissolving 0.0100 mol of HF in 1.00 kg of water. The solution was found to freeze at –0.0236 °C. Calculate the value of i and estimate the percent ionization of HF in this solution. i =____ so HF is ______
A solution is made by dissolving 18.29g of glucose C6H12O2 in 50mL of water at 25C...
A solution is made by dissolving 18.29g of glucose C6H12O2 in 50mL of water at 25C Calculate the molality,molarity, percent mass, Assume density of water is 1.00g/ml
A solution was made by dissolving 5.50 mg of hemoglobin in water to give a final...
A solution was made by dissolving 5.50 mg of hemoglobin in water to give a final volume of 1.00 mL. The osmotic pressure of this solution was 2.10×10-3 atm at 25.0°C.
a solution if phosphoric acid was made by dissolving 10g of H3PO4 in 100mL of water....
a solution if phosphoric acid was made by dissolving 10g of H3PO4 in 100mL of water. the resulting volume was 104mL. calculate the density, mole fraction, molarity, and molality of the solution. assume water has a density of 1g/cm3
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT