In: Physics
A barrel contains a 0.259m layer of oil of density 659kg/m3 floating on water that is 0.331m deep.
a) What is the gauge pressure at the oil-water interface?
b) What is the gauge pressure at the bottom of the barrel?
c) At what depth below the oil surface is the gauge pressure 2630.6738Pa ?
given that ::
density of oil,
=
659kg/m3
density of water,
= 1000
kg/m3
depth of water = 0.331 m
thickness of oil layer = 0.259 m
(a) gauge pressure at the oil-water interface is given as ::
Pressure caused by oil = density x depth x g
where, g = accleration due to gravity = 9.8 m/s2
Pressure caused by oil = (659 kg/m3 ) x 0.259 m x 9.8m/s2 = 1672.6 Pa
(b) gauge pressure at the bottom of the barrel is given as ::
Pressure at bottom = Pressure at oil-water interface + pressure caused by water
pressure caused by water = density x depth x g = (1000 kg/m3 ) x 0.331 m x 9.8m/s2 = 3243.8 Pa
Pressure at bottom = 1672.6 Pa + 3243.8 Pa = 4916.4 Pa
(c) depth below the oil surface is given as ::
gauge pressure, p = 2630.6738 Pa
relative density of oil,
= 0.8
density of oil,
= 
water =
0.8 x 1000 kg/m3 = 800 kg/m3
p = density (
) x depth (h) x
g
where,
= 800
kg/m3 , g = 9.8 m/s2
inserting values in above eq.
h = 2630.6738 Pa / (800 kg/m3 ) (9.8m/s2 )
h = 0.335 m