Question

In: Physics

A barrel contains a 0.259m layer of oil of density 659kg/m3 floating on water that is...

A barrel contains a 0.259m layer of oil of density 659kg/m3 floating on water that is 0.331m deep.

a) What is the gauge pressure at the oil-water interface?

b) What is the gauge pressure at the bottom of the barrel?

c) At what depth below the oil surface is the gauge pressure 2630.6738Pa ?

Solutions

Expert Solution

given that ::

density of oil, = 659kg/m3

density of water, = 1000 kg/m3

depth of water = 0.331 m

thickness of oil layer = 0.259 m

(a) gauge pressure at the oil-water interface is given as ::

Pressure caused by oil = density x depth x g

where, g = accleration due to gravity = 9.8 m/s2

Pressure caused by oil = (659 kg/m3 ) x 0.259 m x 9.8m/s2 = 1672.6 Pa

(b) gauge pressure at the bottom of the barrel is given as ::

Pressure at bottom = Pressure at oil-water interface + pressure caused by water

pressure caused by water = density x depth x g = (1000 kg/m3 ) x 0.331 m x 9.8m/s2 = 3243.8 Pa

Pressure at bottom = 1672.6 Pa + 3243.8 Pa = 4916.4 Pa

(c) depth below the oil surface is given as ::

gauge pressure, p = 2630.6738 Pa

relative density of oil, = 0.8

density of oil, = water = 0.8 x 1000 kg/m3 = 800 kg/m3

p = density () x depth (h) x g

where, = 800 kg/m3 , g = 9.8 m/s2

inserting values in above eq.

h = 2630.6738 Pa / (800 kg/m3 ) (9.8m/s2 )

h = 0.335 m


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