Question

In: Statistics and Probability

1 A well-known brokerage firm executive claimed that 40% of investors are currently confident of meeting...

1

A well-known brokerage firm executive claimed that 40% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 37% of them said they are confident of meeting their goals.

Test the claim that the proportion of people who are confident is smaller than 40% at the 0.10 significance level.

The null and alternative hypothesis would be:

H0:μ=0.4


H1:μ≠0.4

H0:p≥0.4


H1:p<0.4

H0:p≤0.4


H1:p>0.4

H0:μ≥0.4


H1:μ<0.4

H0:p=0.4


H1:p≠0.4

H0:μ≤0.4


H1:μ>0.4



The test is:

two-tailed

left-tailed

right-tailed



The test statistic is: (to 3 decimals)

The p-value is: (to 4 decimals)

Based on this we:

  • Fail to reject the null hypothesis
  • Reject the null hypothesis

2

20% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 356 randomly selected students who receive financial aid, 50 of them volunteered their time. What can be concluded at the α

= 0.05 level of significance?

  1. For this study, we should use
  1. The null and alternative hypotheses would be:   

H0:

  

(please enter a decimal)   

H1:

  

(Please enter a decimal)

  1. The test statistic
  2. The p-value = (Please show your answer to 4 decimal places.)
  3. The p-value is α
  4. Based on this, we should the null hypothesis.
  5. Thus, the final conclusion is that ...

a The data suggest the populaton proportion is significantly lower than 20% at α = 0.05, so there is sufficient evidence to conclude that the percentage of financial aid recipients who volunteer is lower than 20%.

b The data suggest the population proportion is not significantly lower than 20% at α = 0.05, so there is sufficient evidence to conclude that the percentage of financial aid recipients who volunteer is equal to 20%.

c The data suggest the population proportion is not significantly lower than 20% at α = 0.05, so there is insufficient evidence to conclude that the percentage of financial aid recipients who volunteer is lower than 20%.

Solutions

Expert Solution

(1)

Here we have given that,

n=Sample Size=100

=sample proportion of people confident of meeting their goals = 37%=0.37

Claim: To check whether the population proportion of people who are confident is smaller than 40% i.e. 0.40.

The null and alternative hypothesis are as follows,

Versus

where p is the population proportion of people who are confident

This is the left one-tailed test.

Now, we can find the test statistic is as follows,

Z-statistics=

=

= -0.61

The test statistics is -0.61.

Now we find the P-value,

p-value=P(Z > z-statistics)) as this is left one-tailed test

             =P( Z < -0.61)

             = 0.2709 Using standard normal z table see the value corresponding to the z=-0.61

The p-value is 0.2709

Decision:

= level of significance= 0.10

Here p-value (0.2709) greater than (>) 0.10

Conclusion:

We fail to reject the Ho (Null Hypothesis)

There is no sufficient evidence to support the claim the population proportion of people who are confident is smaller than 40% i.e. 0.40.

(2)

Here we have given that,

n=Sample Size=356

x= number of selected students who receive financial aid volunteered their time=50

=sample proportion of people confident in meeting their goals =

Claim: To check whether the population proportion of financial aid recipients who volunteer is lower than 20% i.e. 0.20.

The null and alternative hypothesis are as follows,

Versus

where p is the population proportion of financial aid recipients who volunteer

This is the left one-tailed test.

Now, we can find the test statistic is as follows,

Z-statistics=

=

= -2.83

The test statistics is -2.83.

Now we find the P-value,

p-value=P(Z > z-statistics)) as this is left one-tailed test

             =P( Z < -2.83)

             = 0.0023 Using standard normal z table see the value corresponding to the z=-0.61

The p-value is 0.0023

Decision:

= level of significance= 0.05

Here p-value (0.0023) less than (<) 0.05

Conclusion:

We reject the Ho (Null Hypothesis)

The data suggest that population proportion is significantly lower than 20% at =0.05 so there is sufficient evidence to conclude that the percentage of financial aid recipients who volunteer is lower than 20%.

i.e. option a is correct.


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