In: Statistics and Probability
Using Minitab, calculate the mean, standard deviation, variance, and median of the following four data sets. Comment on the results.
A |
B |
C |
D |
100 |
50 |
50 |
75 |
100 |
75 |
100 |
75 |
100 |
100 |
100 |
75 |
100 |
125 |
100 |
100 |
100 |
150 |
150 |
175 |
Variance = square of standard deviation
Minitab output:
MTB > Mean 'A'.
Mean of A
Mean of A = 100
MTB > StDev 'A'.
Standard Deviation of A
Standard deviation of A = 0
Variance of A
MTB > Let k1=STDEV(A)^2
MTB > print k1
Data Display
K1 0
MTB > Median 'A'.
Median of A
Median of A = 100
MTB > Mean 'B'.
Mean of B
Mean of B = 100
MTB > StDev 'B'.
Standard Deviation of B
Standard deviation of B = 39.5285
Variance of B
MTB > Let k2=STDEV(B)^2
MTB > print k2
Data Display
K2 1562.50
MTB > Median 'B'.
Median of B
Median of B = 100
MTB > Mean 'C'.
Mean of C
Mean of C = 100
MTB > StDev 'C'.
Standard Deviation of C
Standard deviation of C = 35.3553
Variance of C
MTB > Let k3=STDEV(C)^2
MTB > print k3
Data Display
K3 1250.00
MTB > Median 'C'.
Median of C
Median of C = 100
MTB > Mean 'D'.
Mean of D
Mean of D = 100
MTB > StDev 'D'.
Standard Deviation of D
Standard deviation of D = 43.3013
Variance of D
MTB > Let k4=STDEV(D)^2
MTB > print k4
Data Display
K4 1875.00
MTB > Median 'D'.
Median of D
Median of D = 75
Table:
A | B | C | D | |
Mean | 100 | 100 | 100 | 100 |
Standard deviation | 0 | 39.5285 | 35.3553 | 43.3013 |
Variance | 0 |
1562.50 |
1250.00 |
1875.00 |
Median | 100 | 100 | 100 | 75 |
Mean of all four sets of data is same. Other quantities differ.