In: Economics
Find the annual deposit of equal amount needed in Year 2 through Year 5 (End of Year 2 through End of Year 5) to provide for annual withdrawals of $1,500 at the end of years 6, 7, 9 and 10 at an interest rate of 12% per year compounded yearly.
Using formula P = F /(1+i)^t
Present worth of withdrawal at EOY 5 = 1500 / (1+0.12) + 1500 / (1+0.12)^2 + 1500 / (1+0.12)^4 + 1500 / (1+0.12)^5
= 1500 / (1.12) + 1500 / (1.12)^2 + 1500 / (1.12)^4 + 1500 / (1.12)^5
= 4339.49
Annual deposit amount from EOY 2 to EOY 5 = 4339.49 *(A/F,12%,4)
= 4339.49 *(0.12/((1 + 0.12)^4-1))
= 4339.49 *(0.12/((1.12)^4-1))
= 4339.49 *0.209234
= 907.97