In: Physics
A combination work of art/musical instrument is illustrated. Six pieces of identical piano wire (cut to different lengths) are hung from the same support, andmasses are hung from the free end of each wire. Each wire is 1, 2, or 3 units long, and each supports 1, 2, or 4 units of mass. The mass of each wire is negligiblecompared to the total mass hanging from it. When a strong breeze blows, the wires vibrate and create an eerie sound.
Question:
Rank each wire-mass system on the basis of its fundamental frequency.Rank from largest to smallest. To rank items as equivalent, overlap them.
The concept used to solve this problem is standing wave on a string. First use the relation between the string tension, string mass, and string length to calculate the fundamental frequencies for all the wire-mass systems. Finally, compare them on their basis of fundamental frequencies and rank them largest to smallest. Fundamentals Expression for the tension in the spring is, T=Mg Here, T is the tension in the string, M is the hanging mass, and g is the acceleration due to gravity. Expression for the wave velocity is, Here, m/L is the mass density which is constant for all the cases of the wire-mass system, v is the wave velocity, and L is the length of the string. Substitute Mg for the T. The fundamental vibration mode of a stretched string is such that the wavelength is twice of the length of the string. Expression for the fundamental frequency is, Here, Substitute The fundamental frequency fA of wire-mass system A is given as follows: Substitute 2L for LA and 2m for mA in the above equation. Substitute f for Fundamental frequency for the wire-mass system B which has 2 units of mass and 1 unit of length is, The fundamental frequency fB of wire-mass system B is given as follows: Substitute L for LB and 2m for mB in the above equation. Substitute f for The fundamental frequency fC of wire-mass system C is given as follows: Substitute 2L for LC and m for mC in the above equation. Substitute f for Explanation | Common mistakes | Hint for next step From the expression Mass density is constant for all the cases and the tension becomes equal to the weights of the given masses. Hence the fundamental frequency for the wire-mass system is dependent on the mass and length of the wire. The incorrect expression to calculate the fundamental frequency Compare each fundamental frequency and rank them on basis of its fundamental frequency from largest to smallest. The fundamental frequency fD of wire-mass system D is given as follows: Substitute 3L for LD and m for mD in the above equation. Substitute f for Fundamental frequency for the wire-mass system E which has 4 units of mass and 2 units of length is, The fundamental frequency fE of wire-mass system E is given as follows: Substitute 2L for LE and 4m for mE in the above equation. Substitute f for The fundamental frequency fF of wire-mass system F is given as follows: Substitute L for LF and m for mF in the above equation. Substitute f for The ranking from largest to smallest is, Wire-mass system ranked from largest to smallest on their basis of its fundamental frequency as follows Wave speed is proportional its tension which is nothing but the weight of the mass. Fundamental wavelength is proportional to the length of the string whereas its mass of the string is negligible. Fundamental frequency is proportional to the square root of masses hung and inversely proportional to the length of the string. As the length increases fundamental frequency also increases. The incorrect expression to calculate the fundamental frequency Wire-mass system ranked from largest to smallest on their basis of its fundamental frequency as follows is the fundamental frequency.
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