A container ship is heading for port on a fixed course of 30° (= 60°)....

A container ship is heading for port on a fixed course of
30° (= 60°). The captain sets the autopilot and the ship is making 20 Knots (20 Nautical Miles per hour) relative to the water.
• For the first hour, there are no currents affecting the passage of the ship.

• For the second hour there is a current of 4 Knots flowing in direction
30° (= 300°).
• For the third hour there is a current of 6 Knots flowing in direction
15° (= 105°).
Assuming that the full force of any current acts on the ship:

a) How far does the ship travel in the first hour? (1 mark)

b) Sketch the situations for the second and third hour and introduce your vectors
in words.

c) Calculate the speed that the ship makes in the second hour.

d) Calculate the speed that the ship makes in the third hour.

Expert Solution

Your answers are:

a) 37.04km

c) 22.27 knots

d) 16.32 knots

genius_generous answered 2 years ago

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