Kermit (a 6.0kg amorous amphibian) and Miss Piggy (a 10.0kg bacon beauty) find themselves in a...

Kermit (a 6.0kg amorous amphibian) and Miss Piggy (a 10.0kg bacon beauty) find themselves in a pretty precarious predicament. While ascending a mountain in the Alps, they trip on a slippery slope. Since frog friction is very low (u_k?=0.22), Kermit finds himselfhurriedly hurtling toward disaster. Just as Kermit is about to fly over the edge, Miss Piggy lets go of the rope and they both fall to the ground, 227m below. How far apart are they and where will they land? Kermit is 50m away from the edge of the cliff and Miss Piggy is hanging off the edge of the cliff (they are attached by hanging onto a rope). No angle of inclination is given and the direction at which the frogs falls (ex: out horizontally) is not given. The frog is on the cliff and the pig is hanging off the cliff (so the pig will fall down and the frog will slide to the left until it falls). The frog is 50m from the edge of the cliff.

Solutions

Expert Solution

Kermit can be considered as a projectile. Pig is just vertically falling down and it has no horizontal shift.

The average modal slope of Alps mountain is about .

The normal rection of kermit on the slope =

Work done by the friction =

Potential energy of kermit at point A = , If the final velocity down the cliff is v then.

The horizontal component of the velocity of kermit after launch =

And the vertical component =

If the time of flight is t, then,

If the horizontal distance DE = R m, then,

Miss Piggy end up at D. Kermit ends up at E. So they have a distance of aprox. 108m.

genius_generous answered 2 years ago

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