Question

In: Math

Consider the following sample data. Sample A: 10, 17, 24 Sample B: 68, 75, 82 Sample...

Consider the following sample data.

Sample A: 10, 17, 24
Sample B: 68, 75, 82
Sample C: 1,035; 1,042; 1,049


(a) Find the mean and standard deviation for each sample.

Sample A: Sample B: Sample C:
Mean
Sample Standard Deviation


(b) What does this exercise show about the standard deviation?

____The idea is to illustrate that the standard deviation is not a function of the value of the mean.

____The idea is to illustrate that the standard deviation is a function of the value of the mean.

Solutions

Expert Solution

GIVEN:

Sample A 10, 17, 24
Sample B 68, 75, 82
Sample C 1035, 1042, 1049

SOLUTION:

MEAN AND STANDARD DEVIATION OF SAMPLE A:

The mean for sample A is given by,

The standard deviation for sample A is given by,

10 -7 49
17 0 0
24 7 49

  

The mean for sample A is .

The standard deviation for sample A is .

MEAN AND STANDARD DEVIATION OF SAMPLE B:

The mean for sample B is given by,

The standard deviation for sample B is given by,

68 -7 49
75 0 0
82 7 49

  

The mean for sample B is .

The standard deviation for sample B is .

MEAN AND STANDARD DEVIATION OF SAMPLE C:

The mean for sample C is given by,

The standard deviation for sample C is given by,

1035 -7 49
1042 0 0
1049 7 49

  

The mean for sample C is .

The standard deviation for sample C is .

(b) What does this exercise show about the standard deviation?

Standard deviation measures the spread or dispersion of a data distribution. The variability of data points around the mean is same for all three samples given. The idea is to illustrate that the standard deviation is a function of the value of the mean.


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