Question

Please Answer with C code and I will rate! Thank you.

Problem) Write a program that reads 20 integers and stores them in two arrays of 10 elements
each. Then, the program should check if the two arrays have common elements, if yes,
the program should displays the value of each common element and its position in both arrays. Otherwise,
it should display a message and that their elements are different.

Answer 1

#include<iostream>

using namespace std;

int main()

{

    int i, j;

   

    // create arrays of size 10

    int arr1[10];

    int arr2[10];

   

    cout<<"Enter 10 numbers : ";

   

  // read elements in first array

    for( i = 0 ; i < 10 ; i++ )

        cin>>arr1[i];

       

    cout<<"\nEnter 10 numbers : ";

   

    // read elements in second array

    for( i = 0 ; i < 10 ; i++ )

        cin>>arr2[i];

       

    // store the number of common elements

    int count = 0;

   

    // traverse first array

    for( i = 0 ; i < 10 ; i++ )

    {

        int index = -1;

       

        // travserse array 2 to find common elements with i th element of array 1

        for( j = 0 ; j < 10 ; j++ )

        {

            // if the jth element is common

            if( arr1[i] == arr2[j] )

                index = j;

        }

       

        // if the i th element is common

        if( index != -1 )

            cout<<arr1[i]<<" is common and occurs at index "<<i<<" in 1st array and index "<<index<<" in 2nd array."<<endl;

    }

   

    return 0;

}

Sample Output