Suppose that a jar contains 8 green jelly beans and 10 blue jelly beans. Answer the...

Suppose that a jar contains 8 green jelly beans and 10 blue jelly beans.

Answer the following questions. Round your answers to four decimal places.

(a) How many ways can you randomly pick out four beans from the jar?

(b) What is the probability that you randomly pick out four beans and exactly two of them are green jelly beans?

(c) What is the probability that you pick up a green jelly bean (without putting it back into the jar), then pick up a blue bean second?

Expert Solution

a) Number of ways = 18C4 = 18!/(4! * 14!) = 3060

b) P(exactly two are green) = (8C2 * 10C2)/18C4 = 0.4118

c) Probability = 8/18 * 10/17 = 0.2614

orchestra answered 1 year ago

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