In: Statistics and Probability
2. The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40students with a mean MCAT score of 32.2 with a standard deviation of 4.2. Test the claim that the studentsthat took the Kaplan tutoring have a mean score greater than 29.5 at a 0.05 level of significance.(For fullcredit need to draw the curve and shade the area)
H0: Test Stat:
H1:
Conclusion:
Let be the mean of MCAT score.
We want ot test the claim that the students that took the Kaplan tutoring have a mean score greater than 29.5
The null hypothesis will be
I.e mean score is equal to 29.5
vs the alternative hypothesis will be
.i.e mean score greater than 29.5
The sample of 40 students have mean MCAT score of 32.2 with a standard deviation of 4.2.
The sample mean is
and the sample standard deviation
s = 4.2
The test statistic is given as
= 4.065786
Now obtaining the critical value from the t-table
Dicision rule:
Reject H0 if t ( calculated value ) > t( critical value)
i.e
Since
t( calculted value) =4.065786 > t (critical value) =1.6849
We reject the null hypothesis
The shaded region is critical region since this is upper tailed test. Since our test statistic fall in this region , we reject the null hypothesis