In: Economics
Let suppose two combinations of price and quantity are -
P = $5 , Qd = 45 units
P = $10 , Qd = 20 units
Slope of the demand curve = ∆Qd/∆P = -25/5 = -5.
At P = 10 , Q = 20 , the equation of demand curve is
P - 10 = (∆Q/∆P)[Q - 20]
Or, P - 10 = -5*(Q - 20)
Or, P - 10 = - 5Q + 100
Or, 5Q = 100 + 10 - P
Or, 5Q = 110 - P
Or, Q = (110/5) - (1/5)P
Or, Q = 22 - 0.2P ...... This is the demand function.
P = 110 - 5Q ..... Inverse demand function.
Revenue function = TR = P*Q
Revenue (R) = (110 - 5Q)*Q = 110Q - 5Q^2 ..Revenue function
Variable cost equation is = 10Q + 5Q^2
Fixed Cost = 50.
Profit equation (π) = R - VC - FC
π = 110Q - 5Q^2 - (10Q + 5Q^2) - 50
π = 110Q - 5Q^2 - 10Q - 5Q^2 - 50
π = 100Q - 10Q^2 - 50 ...... This is profit equation.
At profit maximising level F.O.C of profit (π) function w.r.t Q = 0.
Therefore, dπ/dQ = d/dQ(100Q - 10Q^2 - 50) = 0
Therefore, 100 - 20Q = 0
Or, 20Q = 100
Or, Q* = 100/20 = 5.
Therefore, at Profit maximising level there should produce 5 units of output. (Answer).