Question

In: Statistics and Probability

The data below represents the weight loss (in pounds) for people on three different exercise programs....

The data below represents the weight loss (in pounds) for people on three different exercise programs. At the 0.01 significance level, does it appear that a difference exists in the true mean weight loss produced by the three exercise programs.

Exercise A

Exercise B

Exercise C

7.1

3.1

6.7

8.0

2.2

8.1

7.5

5.0

5.0

6.8

4.4

9.0

a) State the null and alternative hypotheses.

b) Find the P-value. STATE THE CALCULATOR COMMAND YOU USE.

c) State whether you should reject or fail to reject the null hypothesis. Justify your answer.

d) State your conclusion in non-technical terms. Which exercise program appears to be the least effective based on the sample data?

Solutions

Expert Solution

Mean n Std. Dev
Exercise A 7.35 4 0.520
Exercise B 3.68 4 1.263
Exercise C 7.20 4 1.745
Total 6.08 12 2.118

Part a)

To Test :-
H0 :- µ1 = µ2 = µ3 = 0 i.e There is no difference in the treatment means
H0 :- µ1 = µ2 = µ3 ≠ 0 i.e Some means are different

Part b)

ANOVA table
Source SS    df MS F    p-value
Treatment 34.605 2 17.3025 10.57 0.0043
Error 14.738 9 1.6375
Total 49.343 11

Excel formula

FDIST(10.5664,2,9) = 0.004349242

Part c)

Decision based on P value
Reject null hypothesis if P value < α = 0.01
Since P value = 0.0043 < 0.01, hence we reject the null hypothesis
Conclusion :- Treatment means differs

Part d)

There is sufficient evidence to conclude that a difference exists in the true mean weight loss produced by the three exercise programs.

Lookinat at the averages we can say that Exercise B is lease effective.


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