In: Chemistry
At 20
ssume one liter of solution is present. Convert the volume of 1 L to milliliters. Next multiply the volume in milliliters with the density provided to obtain the mass of the total solution. (Don't confuse this mass with the mass used to calculate density as it is the mass of the entire solution not just the solvent!)
1 L * ( 1000 mL / 1 L ) * ( 1.0344 g / mL) = 1034.4 grams of solution
Now that you have the mass of the solution you need to find the mass of just the solvent component. Do this by subtracting the grams of ammonium chloride present in the solution. The mass of the ammonium chloride is equal to the number of moles (which is based on our chose volume of one liter) multiplied by the molar mass of ammonium chloride. The difference between the solution mass and the mass of the solute is the mass of the solvent.
1034.4 g - [ ( 2.32 mol ) * ( 53.50 g / mol ) ] = 910.28 grams of water (the solvent) or .91028 kilograms.
Finally divide the moles of ammonium chloride (again provided from our chosen volume of 1 L) by the mass of the water (in kg!) to find the molality of the solution.
2.32 mol * ( 1 / .91208 kg ) = 2.54 mol NH4Cl / kg H2O.
All together:
1 L * ( 1000 mL / 1 L ) * ( 1.0344 g / mL) = 1034.4
grams of solution
1034.4 g - [ ( 2.32 mol ) * ( 53.50 g / mol ) ] = 910.28 grams of
water (the solvent) or .91028 kilograms.
2.32 mol * ( 1 / .91208 kg ) = 2.55 mol NH4Cl / kg
H2O.
so answer is A) 2.55