In: Statistics and Probability
In a survey of 4004 adults, 701 oppose allowing transgender students to use the bathrooms of the opposite biological sex. Construct a 99% confidence interval for the population proportion. Interpret the results.
Let p be the population proportion of appose allowing transgender students to use the bathrooms of the opposite biological sex.
n = number of adults in a survey = 4004.
X: Number of adults appose allowing transgender students to use the bathrooms of the opposite biological sex. = 701
phat : sample proportion
phat = X / n = 701 / 4004 =0.1751
Since the distribution of sampling proportion is normal.
We use normal distribution to find confidence interval for population proportion.
99% Confidence interval for population proportion is
Alpha: level of significance = 0.01
From normal probability table
Hence 99% confidence interval is
=(0.1751 -0.0155, 0.1751+ 0.0155)
=(0.1596, 0.1906).
Interpretation: The 99% true value of population proportion lies between 15.96% to 19.06%.