In: Statistics and Probability
1. The following 10 observations are a random sample from a normal population. 7.4 7.1 6.5 7.6 6.3 7.2 8.1 6.8 7.1 7.5
a) Find the mean and standard deviation of this data.
b)(5marks)TestH0: μ=7.4versusH1: μ<7.4atα=0.05.
Solution:
x | x2 |
7.4 | 54.76 |
7.1 | 50.41 |
6.5 | 42.25 |
7.6 | 57.76 |
6.3 | 39.69 |
7.2 | 51.84 |
8.1 | 65.61 |
6.8 | 46.24 |
7.1 | 50.41 |
7.5 | 56.25 |
∑x=71.6 | ∑x2=515.22 |
a ) Mean ˉx=∑xn
=7.4+7.1+6.5+7.6+6.3+7.2+8.1+6.8+7.1+7.5/10
=71.6/10
=7.16
Sample Standard deviation S=√∑x2-(∑x)2nn-1
=√515.22-(71.6)210/9
=√515.22-512.656/9
=√2.564/9
=√0.284/9
=0.5337
b )This is the Left tailed test .
The null and alternative hypothesis is ,
H0 : = 7.4
Ha : < 7.4
Test statistic = t
= ( - ) / S / n
= (7.16-7.4) / 0.53 / 10
= −1.432
Test statistic = t = −1.432
P-value =0.093
= 0.05
P-value >
0.093 > 0.05
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that