In: Economics
A construction company is purchasing a new Tractor for over the road use. The IRS classifies this as 3-year property. The truck costs $280000.
a) Determine the depreciation allowance for each year using SLN method.
Year 1 $
Year 2 $
Year 3 $
Year 4 $
b) Determine the depreciation allowance for each year using DDB method.
Year 1 $
Year 2 $
Year 3 $
Year 4 $
c) Determine the depreciation allowance for each year using MACRS.
Year 1 $
Year 2 $
Year 3 $
Year 4 $
d) Using a 10% MARR calculate the present worth of the depreciation for each of the 3 methods above.
PWa = $
PWb = $
PWc = $
Price of Truck $280000
A.Using SLM depreciation life of asset = 4 yr
Depriciation = $280000/4 yr = $70000/yr
1yr; Depreciation = $ 70000/yr
2yr Depreciation = $70000/yr
3yr; Depreciation = $70000/yr
4 yr; Depreciation = $ 70000 / yr.
B. Double Declining Balance: under this method the depreciation is double of the SLM. For example if under SLM depreciation is $10000 / year then under DDB it would be $20000/ year.
Using the previous calculation we can easily find the DDB.
1 yr; DDB = 2×70000 = $ 140000
2yr ; DDB = $(280000-140000)×(2×0.25) = $70000
3yr ; DDB = $(140000-70000)×(2×0.25) = $35000
4yr; DDB = 35000 ×0.5 = $17500
C. Calculation of MACRS
Year | MACRS | Depriciation | |
1 | 33.33 | 280000×0.3333= $93324 | |
2 | 44.45 | 280000×0.4445= $124460 | |
3 | 14.81 | 280000×0.1481 = $41468 | |
4 | 7.41 | 280000× 0.0741 = $ 20748 |
D. Present Value
= $221890
= $223372
= $ 233026