In: Statistics and Probability
Snow White recieves a basket of 11 apples, out of which 2 of
them are poisoned. She decides to eat 4 of them. Let X1 denote the
number of unpoisoned apples that she eats.
Check all that are true about X1.
A. We can model X1 with a collection of
trials
B. The trials are independent
C. The trials have two outcomes
D. The trials have the same probability of
success.
E. There are a set number of trials
Snow White recieves an unlimited basket of apples, each of which
has a 0.4 chance of being poisoned, regardless of the status of
other apples. She makes the questionable choice to keep eating them
until she eats a poisoned one. Let X2 denote the number of
unpoisoned apples that she eats.
Check all that are true about X2.
A. The trials have two outcomes
B. We can model X2 with a collection of
trials
C. There are a set number of trials
D. The trials are independent
E. The trials have the same probability of
success.
Snow White recieves a basket of 4 apples, all of whom are either
poisoned or not. There is a 0.4 chance they are poisoned. She
decides to eat all of them. Let X3 denote the number of unpoisoned
apples that she eats.
Check all that are true about X3.
A. The trials have the same probability of
success.
B. There are a set number of trials
C. The trials are independent
D. We can model X3 with a collection of
trials
E. The trials have two outcomes
Snow White recieves a basket of 4 apples, each of which has a 0.4
chance of being poisoned, regardless of the status of other apples.
She decides to eat all of them. Let X4 denote the number of
unpoisoned apples that she eats.
Check all that are true about X4.
A. The trials are independent
B. We can model X4 with a collection of
trials
C. The trials have two outcomes
D. There are a set number of trials
E. The trials have the same probability of
success.
Which of the following are a binomial random variable?
A. X1
B. X2
C. X4
D. X3
Answer:
For X1:
Since apples are drawn without replacement so trials are not independent. Since trials are not independent so probability of success is not same for each trial. Each trial has only two outcomes : unpoisoned and poisoned
Number of trials is fix and equal to 4.
So correct option is:
C. The trials have two outcomes
E. There are a set number of trials
A. We can model X1 with a collection of trials
Note: It can be modeled as hypergeometric distribution.
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For X2:
A. The trials have two outcomes
B. We can model X2 with a collection of
trials
C. The trials have the same probability of
success.
D. The trials are independent
Note: It can be modeled as geometric distribution.
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For X3:
A. The trials have two outcomes
B. There are a set number of trials
C. We can model X3 with a collection of
trials
D. The trials have the same probability of
success.
E. The trials are independent
Note: It can be modeled as binomial distribution.
-------------------------------------------------------
For X4:
A. The trials are independent
B. We can model X4 with a collection of
trials
C. The trials have the same probability of
success.
D. There are a set number of trials
E. The trials have two outcomes
Note: It can be modeled as binomial distribution.
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Which of the following are a binomial random variable?
B. X4
C. X3
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